SOLUTION: Divide {{{(6z^4-4z^3+9z^2+4z+5)}}} / {{{(z^2-z+2)}}}

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Question 44624: Divide
%286z%5E4-4z%5E3%2B9z%5E2%2B4z%2B5%29 / %28z%5E2-z%2B2%29
Answer by pvaka(23) About Me  (Show Source):
You can put this solution on YOUR website!


(6z^4-4z^3+9z^2+4z+5)/(z^2-z+2)
(1)z^2-z+2 (6z^2)= 6z^4-6z^3+12z^2 substract from 6z^4-4z^3+9z^2+4z+5 = 2z^3-3z^2-4z+5
(2)z^2-z+2 (2z)=2z^3-2z^2+47 substract from 2z^3-3z^2-4z+5 = -z^2-8z+5
(3)z^2-z+2 (-1)=-z^2+z-2 substract from -z^2-8z+5 =-9z+7 REMAINDER
SOLUTION: 6z^2+2z-1+(-9z+7)/z^2-z+2