SOLUTION: (x+6)(x-19)(x+1)=0 what are the x's???

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Question 417500: (x+6)(x-19)(x+1)=0 what are the x's???
Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(x+6)(x-19)(x+1)=0 what are the x's???
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Since the product is zero, one of those factors must be zero.
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x+6 = 0 or x-19 = 0 or x+1 = 0
x = -6 or x = 19 or x = -1
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Cheers,
Stan H.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

The factor theorem states that a polynomial f(x) has a factor (x − k) if and only if f(k) = 0

f(x) = (x+6)(x-19)(x+1)=0     |As Stated in the Question, therefore:

 (x+6)= 0

   x = -6

 (x-19)= 0

   x = 19

 (x+1)=0

   x = -1

 Solution Set is: -6,-1,19