Question 360110: (2+4i)/2i
Answer by CharlesG2(834)   (Show Source):
You can put this solution on YOUR website! (2+4i)/2i
when you divide two complex numbers, you must multiply the numerator and the denominator by the complex congugate of the denominator
(2 + 4i)/2i
-2i is the complex conjugate of 2i
(2 + 4i)/2i * (-2i)/(-2i)
-2i(2 + 4i)/(2i * -2i)
(-4i - 8i^2)/(-4i^2)
(-4i + 8)/4 (note i^2 = -1)
2 - i
|
|
|
