Question 326763: I could really use some help with this problem:
3x^2 + 6 3/4 x + 6 3/4 = 1 1/2 x^2 + 2 1/4 x
Any help would be greatly appreciated!!! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 3x^2 + 6 3/4 x + 6 3/4 = 1 1/2 x^2 + 2 1/4 x
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3x^2 + (27/4)x + (27/4) = (3/2)x^2 + (9/4)x
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Multiply thru by 4 to get rid of the fractions:
12x^2 + 27x + 27 = 6x^2 + 9x
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Combine:
6x^2 + 18x + 27 = 0
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2x^2 + 6x + 9 = 0
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x = [-6 +- sqrt(36 - 4*2*9)]/(4)
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x = [-6 +- sqrt(-36)]/4
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x = [-6 +- 6i]/4
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x = (-3/2) +- (3/2)i
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Cheers,
Stan H.
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