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| Question 30908:  perform the indicated operation and simplify:
 1+3i/1-2i
 Answer by kietra(57)
      (Show Source): 
You can put this solution on YOUR website! (1+3i)/(1-2i) In imaginary numbers, there's a rule that you can never have an i in the denominator.  To get rid of that, you multiply by the inverse of (1-2i) which is (1+2i) in both the denominator and numerator.  You must use FOIL to multiply the numbers.
 (1+3i)/(1-2i)* (1+2i)/(1+2i).  Multiply numerators together and denominators.
 (1+3i)(1+2i)/(1-2i)(1+2i)
 (1 + 2i + 3i + 6i^2)/(1 -2i + 2i - 4i^2)
 (1 + 5i + 6(-1))/(1 -4(-1))
 (1-6 + 5i)/(1 + 4)
 (-5 + 5i)/(5) =now reduce
 5(-1 + i)/5
 -1 + i
 
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