SOLUTION: solve 2x^2 = 3x + 2 by graphing. If exact roots cannot be found, state the consecutive integers between which the root are located.

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Question 289509: solve 2x^2 = 3x + 2 by graphing. If exact roots cannot be found, state the consecutive integers between which the root are located.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
2x%5E2+=+3x+%2B+2
f%28x%29=2x%5E2+-3x+-+2=0
Graph the function the find the x values when it equals zero.
+graph%28+300%2C+300%2C+-3%2C+3%2C+-3%2C+3%2C++2x%5E2-3x-2%29+
Now looking at the graph, you can guess the x values where f(x)=0.
Looks like x=2 is one of those points.
Plug it into the function and check.
f%282%29=2%282%29%5E2-3%282%29-2=2%284%29-6-2=8-6-2=0
x=2 is a root.
I leave it to you to find the other.
Guess and check.