SOLUTION: Between 1970 and 1990, the population of Buffalo, New York, decreased at the rate or 0.82% per year. The population, P, in year t is given by {{{P=1025000(0.9917^t)}}} where

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: Between 1970 and 1990, the population of Buffalo, New York, decreased at the rate or 0.82% per year. The population, P, in year t is given by {{{P=1025000(0.9917^t)}}} where      Log On


   

Question 27035: Between 1970 and 1990, the population of Buffalo, New York, decreased at the rate or 0.82% per year. The population, P, in year t is given by
P=1025000%280.9917%5Et%29
where t=0 corresponds to 1980. Find the population in 1970.
Answer by mbarugel(146) About Me  (Show Source):
You can put this solution on YOUR website!
Given that the formula is:
P=1025000+%280.9917%5Et%29
where t=0 corresponds to 1980, then we must simply evaluate this formula at t=-10, which corresponds to 1970
P=1025000+%280.9917%5E%28-10%29%29+=+1114091
So the population in 1970 was 1,114,091.