Question 252963: Can you help me with the corrections for my math test i failed and i want to do better. What we are doing are radicals/complex numbers.
3 is the index square root and inside of the square root is 32x to the sixth y to the ninth
You can put this solution on YOUR website! So, your question is: cube root(32x^6y^9).
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To solve cube roots you want triple of something in order to pull it out. Let's write out everything:
cuberoot [ 2*2*2*2*2*x*x*x*x*x*x*y*y*y*y*y*y*y*y*y]
look for triples.
cuberoot [ {2*2*2}*2*2*{x*x*x}*{x*x*x}*{y*y*y}*{y*y*y}*{y*y*y}]
notice we have a triple of 2's, 2 triples of x's and 3 triples of y's. We can take those out.
What ever is not a triple stays inside. It looks like this: *cuberoot(2*2) *cuberoot(4)
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