SOLUTION: (2+3i)(6+4i)=12+8i+18i+12i^2 =12+26i-12 (since i^2 = -1) =26i ans

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: (2+3i)(6+4i)=12+8i+18i+12i^2 =12+26i-12 (since i^2 = -1) =26i ans      Log On


   

Question 250966: (2+3i)(6+4i)=12+8i+18i+12i^2
=12+26i-12 (since i^2 = -1)
=26i ans
Answer by vksarvepalli(154) About Me  (Show Source):
You can put this solution on YOUR website!
(2+3i)(6+4i)=12+8i+18i+12i^2
=12+26i-12 (since i^2 = -1)
=26i ans