Question 236724: i really dont know but its about remain restriction and could you please help me?
the problem is:
Y=5X/3X+9?
can you please help me? Found 2 solutions by College Student, solver91311:Answer by College Student(505) (Show Source):
You can put this solution on YOUR website! If I understand correctly, you're trying to find the value of Y, right?
Since you have an x to the power of 1 in the numerator and in the denominator, we can cancel the x from the equation. So:
This is the same as to say:
So now we look for a common denominator, which would be 3.
Now you can add the fractions as they have same denominator.
and that you want to describe any restrictions on the domain (not the "remain") of the function.
The domain of any rational function must exclude any value of the independent variable (the in this case) that would make any denominator in the function equal zero. You have but one denominator here, so let's set it equal to zero and solve:
So now we know that -3 is the value that must be excluded from the domain.
All other real values for the independent variable are acceptable values, therefore the domain of the given function is:
Next time you post a problem, use parentheses to make it clear what things go together. The way you posted your problem it was equally likely that you meant either:
or
Had you written: y = 5x/(3x + 9) your meaning would have been clear.
