SOLUTION: If {{{ 3 + 2i }}} is a solution for {{{ x^2+mx+n=0 }}}, where m and n are real numbers, what is the value of m?

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Question 175769: If +3+%2B+2i+ is a solution for +x%5E2%2Bmx%2Bn=0+, where m and n are real numbers, what is the value of m?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
If +3+%2B+2i+ is a solution for +x%5E2%2Bmx%2Bn=0+, where m and n are real numbers, what is the value of m?
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If 3+2i is a solution then 3-2i is a solution.
Then (x-3+2i)(x-3+2i) is the form of the quadratic
Then (x-3)^2-(2i)^2 is the form of the quadratic.
Then x^2 -6x + 9 + 4 is the form of the quadratic
Then x^2 -6x + 13 = x^2 + mx + n
m=-6
n = 13
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Cheers,
Stan H.