SOLUTION: well i have to solve this equation: x^2-6x+25 and put it in a+bi form. can you please show me how to do this

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Question 170874This question is from textbook Algebra 2
: well i have to solve this equation: x^2-6x+25 and put it in a+bi form. can you please show me how to do this This question is from textbook Algebra 2

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I assume that you want to solve x%5E2-6x%2B25=0


x%5E2-6x%2B25=0 Start with the given equation.


Notice we have a quadratic equation in the form of ax%5E2%2Bbx%2Bc where a=1, b=-6, and c=25


Let's use the quadratic formula to solve for x


x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


x+=+%28-%28-6%29+%2B-+sqrt%28+%28-6%29%5E2-4%281%29%2825%29+%29%29%2F%282%281%29%29 Plug in a=1, b=-6, and c=25


x+=+%286+%2B-+sqrt%28+%28-6%29%5E2-4%281%29%2825%29+%29%29%2F%282%281%29%29 Negate -6 to get 6.


x+=+%286+%2B-+sqrt%28+36-4%281%29%2825%29+%29%29%2F%282%281%29%29 Square -6 to get 36.


x+=+%286+%2B-+sqrt%28+36-100+%29%29%2F%282%281%29%29 Multiply 4%281%29%2825%29 to get 100


x+=+%286+%2B-+sqrt%28+-64+%29%29%2F%282%281%29%29 Subtract 100 from 36 to get -64


x+=+%286+%2B-+sqrt%28+-64+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


x+=+%286+%2B-+8%2Ai%29%2F%282%29 Take the square root of -64 to get 8%2Ai.


x+=+%286+%2B+8%2Ai%29%2F%282%29 or x+=+%286+-+8%2Ai%29%2F%282%29 Break up the expression.


x+=+%286%29%2F%282%29+%2B+%288%2Ai%29%2F%282%29 or x+=++%286%29%2F%282%29+-+%288%2Ai%29%2F%282%29 Break up the fraction for each case.


x+=+3%2B4%2Ai or x+=++3-4%2Ai Reduce.


x+=+3%2B4%2Ai or x+=+3-4%2Ai Simplify.


So the answers are x+=+3%2B4%2Ai or x+=+3-4%2Ai