.
Consider function  
    sin(x)*(sin(x)-2)+1) = sin^2(x) - 2sin(x) + sin(x) = sin^2(x) - sin(x) = sin(x)*(sin(x) -1).
In vicinity of  x=  this function is negative (except of its value at x=
  this function is negative (except of its value at x=  , where it is zero).
Therefore, in vicinity of  x =
, where it is zero).
Therefore, in vicinity of  x =  the given expression, which is the square root of sin(x)*(sin(x)-2)+1),
is not defined, at all, as a real function, so the question  "is it continuous or not"
even can not be posed: this function does not exist in real domain.
  the given expression, which is the square root of sin(x)*(sin(x)-2)+1),
is not defined, at all, as a real function, so the question  "is it continuous or not"
even can not be posed: this function does not exist in real domain.
Solved.
It is a mathematical joke problem (a kind of TRAP) to check your alertness.