Question 1193427: A vendor sells 60% of apples he had and throws away 15% of the remainder. Next day, he sells 50% of the remainder and throws away the rest. What percent of the apples does the vendor throws away?
Found 2 solutions by Boreal, MathTherapy:
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! After he sells 60% he has 40% left. Use 100, so he has 40 left
He throws away 15% of 40 which is 6. He now has 34 apples.
He sells half of them (17) an he throws away the other 17.
He threw away 23 altogether, so the answer is 23%
Answer by MathTherapy(10549)  (Show Source):
You can put this solution on YOUR website!
A vendor sells 60% of apples he had and throws away 15% of the remainder. Next day, he sells 50% of the remainder and throws away the rest. What percent of the apples does the vendor throws away?
Let 100% or 1 represent the original number of apples
After selling 60% (.6), he then has 1 - .6, or .4 remaining
After "tossing" 15% (.15) of the remainder, he has "tossed" .15(.4) = .06, and then has .4 - .06 = .34 remaining
Selling 50% (.5) of the remainder, or .5(.34) = .17 leaves him with .34 - .17 = .17, which was tossed.
Adding the "tossed" gives us: .06 + .17 = .23, or 23%.
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