SOLUTION: Two sides of a square lie along the lines 2y = 20 - 3x and 3x + 2y = 48. Find the area of the square.

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: Two sides of a square lie along the lines 2y = 20 - 3x and 3x + 2y = 48. Find the area of the square.      Log On


   



Question 1186110: Two sides of a square lie along the lines 2y = 20 - 3x and 3x + 2y = 48. Find the area of the square.
Answer by ikleyn(52847) About Me  (Show Source):
You can put this solution on YOUR website!
.
The two lines are parallel.


The distance between them is


    Q = abs%2848-20%29%2Fsqrt%283%5E2+%2B+2%5E2%29 = 28%2Fsqrt%2813%29


(see my post https://www.algebra.com/algebra/homework/Finance/Finance.faq.question.1186108.html )


This distance is the side length of the square.


THEREFORE, the area of the square is  Q%5E2, i.e.


    area = Q%5E2 = 28%5E2%2F13 = 784%2F13 = 60.30769  (rounded).        ANSWER

Solved and explained.