SOLUTION: Use De Moivre's Theorem to show that integral powers of (-1 + i)/(√2) are real, and which are imaginary

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Question 1181165: Use De Moivre's Theorem to show that integral powers of (-1 + i)/(√2) are real, and which are imaginary
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Use De Moivre's Theorem to show that integral powers of (-1 + i)/(√2) are real, and which are imaginary
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The complex number  z = %28-1%2Bi%29%2Fsqrt%282%29  has the modulus 1  and the argument  3pi%2F4.


So, in cis-form,  z = 1%2Acis%283pi%2F4%29 = cis%283pi%2F4%29.


It means that z itself and all integer degrees of z have the modulus 1, i.e. lie on a unit circle 
in complex plane.


According to De Moivre's theorem, the degrees of z are


    z%5E1 = cis%283pi%2F4%29

    z%5E2 = cis%286pi%2F4%29 = cis%283pi%2F2%29 = -i   (pure imaginary)

    z%5E3 = cis%289pi%2F4%29

    z%5E4 = cis%2812pi%2F4%29 = cis%283pi%29 = -1    (real number)
    
    z%5E5 = cis%2815pi%2F4%29

    z%5E6 = cis%2818pi%2F4%29 = cis%289pi%2F2%29 = i   (pure imaginary)

    z%5E7 = cis%2821pi%2F4%29

    z%5E8 = cis%2824pi%2F4%29 = cis%286pi%29 = 1     (real number)


The degrees of z that follow after  z%5E8,  repeat these numbers cyclically


    z%5E9 = z%5E1  

    z%5E10 = z%5E2 = -i  (imaginary)

    z%5E11 = z%5E3

    z%5E12 = z%5E4 = -1  (real number)



    z%5E13 = z%5E5  

    z%5E14 = z%5E6 =  i  (imaginary)

    z%5E15 = z%5E7

    z%5E16 = z%5E8 =  1  (real number)


So, the pattern is this:  z%5En  is real     if and only n is of the form  n = 4k  (i.e. n is a multiple of 4), and

                          z%5En  is pure imaginary if and only n is of the form  n = 4k+2  (i.e. n gives the remainder of 2 when is divided by 4).



ANSWER.  z%5En  is real if and only if  n == 0  mod 4;

         z%5En  is pure imaginary if and only if  n == 2  mod 4.

Solved.