SOLUTION: Elise saved $184. She bought a scarf, a necklace, and a notebook. After her purchases, she still had $39.50. The scarf cost three-fifths the cost of the necklace, and the not

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: Elise saved $184. She bought a scarf, a necklace, and a notebook. After her purchases, she still had $39.50. The scarf cost three-fifths the cost of the necklace, and the not      Log On


   



Question 1160953: Elise saved $184.
She bought a scarf, a necklace, and a notebook.
After her purchases, she still had $39.50.
The scarf cost three-fifths the cost of the necklace, and the notebook was one-sixth as much as the scarf.
What was the cost of each item?
How much more did the necklace cost than the notebook

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Elise saved $184.
She bought a scarf, a necklace, and a notebook.
After her purchases, she still had $39.50.
Therefore the total for purchases: 184 - 39.50 = $144.50
let s = cost of scarf
let n = cost of necklace
let b = cost of notebook
s + n + b = 144.50
:
The scarf cost three-fifths the cost of the necklace,
s = 3%2F5n
find n in terms of s
3%2F5n = s
3n = 5s
n = 5%2F3s
:
the notebook was one-sixth as much as the scarf.
b = 1%2F6s
:
replace n and b in the first equation
s + 5%2F3s + 1%2F6s = 144.50
multiply by 6 get rid of the denominators
6s + 2(5s) + s = 6(144.50)
6s + 10s + s = 867
17s = 867
s = 867/17
s = $51 for the scarf
then
n = 5%2F3*51
n = $85 for the necklace
and
b = 1/6)))*51
b = $8.50 for notebook
:
How much more did the necklace cost than the notebook
85 - 8.50 = $76.50 more for the necklace