SOLUTION: (x-3)^2 +(y-2)^2=16 find the equation of the tangent line at the point (-2,1)

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Question 1159059: (x-3)^2 +(y-2)^2=16 find the equation of the tangent line at the point (-2,1)
Found 2 solutions by greenestamps, MathLover1:
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


The given point is not on the given curve....

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

The given point (-2,1) is not on the given curve.
check:
%28-2-3%29%5E2+%2B%281-2%29%5E2=16+
%28-5%29%5E2+%2B%28-1%29%5E2=16+
25+%2B1=16+
26%3C%3E16