SOLUTION: -2i + (9 − 3i) − (6 − 10i) as a complex number in standard form

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Question 1111140: -2i + (9 − 3i) − (6 − 10i) as a complex number in standard form
Found 3 solutions by Alan3354, Theo, math_helper:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
-2i + (9 - 3i) - (6 - 10i) as a complex number in standard form
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-2i + (9 - 3i) - (6 - 10i) = -2i + 9 - 3i - 6 + 10i
= 9-6 -2i-3i+10i
= 3 + 5i

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
you add all the complex parts together and all the real parts together to come up with the answer.

-2i + (9 - 3i) - (6 - 10i) would be simplified to be:

-2i + 9 - 3i - 6 + 10i.

combine real parts and combine imaginary parts to get:

3 + 5i





Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
Just combine "like" terms (real and imaginary).
-2i + (9 − 3i) − (6 − 10i) = (9-6) + i*(-2-3+10) = +highlight%28+3%2B5i+%29+