SOLUTION: (3x+4yi)(3+5i)=6+2i

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Question 1109371: (3x+4yi)(3+5i)=6+2i
Answer by math_helper(2461) About Me  (Show Source):
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(3x+4yi)(3+5i) = 6+2i
+9x%2B15xi%2B12yi%2B20yi%5E2+=+6%2B2i
+9x%2B15xi%2B12yi+-20y+=+6%2B2i
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Grouping real and imaginary parts:
+%289x-20y%29+%2B+%2815x%2B12y%29i+=+6%2B2i+
Set LHS real = RHS real and LHS imaginary = RHS imaginary:
+9x+-+20y+=+6+
+15x+%2B12y+=+2+
You now have two equations with two unknowns, and you should be able to
solve to get:
x = 14/51, y=-3/17
or approximately:
x=0.27451, y=-0.17647