SOLUTION: An object is dropped from a balloon 3600 feet above the ground. Find the time it takes to reach the ground if the height of the object is given by the equation h(t) = –16t^2+ 3600

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: An object is dropped from a balloon 3600 feet above the ground. Find the time it takes to reach the ground if the height of the object is given by the equation h(t) = –16t^2+ 3600      Log On


   

Question 1108570: An object is dropped from a balloon 3600 feet above the ground. Find the time it takes to reach
the ground if the height of the object is given by the equation h(t) = –16t^2+ 3600
Found 2 solutions by Alan3354, josmiceli:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
An object is dropped from a balloon 3600 feet above the ground. Find the time it takes to reach
the ground if the height of the object is given by the equation h(t) = –16t^2+ 3600
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when h(t) = 0
–16t^2+ 3600 = 0
Solve for t.
Ignore the negative solution.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+h%28t%29+=+-16t%5E2+%2B+3600+
The object is dropped at +t=0+
+h%280%29+=+-16%2A0%5E2+%2B+3600+
+h%280%29+=+3600+ ft
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You need to find +t+ in sec when
+h%28t%29+=+0+ ( the height above ground is zero )
+-16t%5E2+%2B+3600+=+0+
+16t%5E2+=+3600+
+t%5E2+=+225+
+t+=+15+
The object hits the ground in 15 sec