SOLUTION: The length of a rectangle is three times as long as its width. Its area is 675 square feet. a. Write an equation that demonstrates the given information. b. Find the dimensions o

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: The length of a rectangle is three times as long as its width. Its area is 675 square feet. a. Write an equation that demonstrates the given information. b. Find the dimensions o      Log On


   

Question 1108569: The length of a rectangle is three times as long as its width. Its area is 675 square feet.
a. Write an equation that demonstrates the given information.
b. Find the dimensions of the rectangle.
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
a.) L = 3W
and
Area = LW = 3W%5E2 = 675 sq ft
—
b) +3W%5E2+=+675+
To solve for W, first divide both sides by 3:
+W%5E2+=+225+
Take the square root of both sides
+W+=+15ft+ —> +L+=+45ft+

—
Check:
A = 15*45 = 675 (ok)