You forgot to point in the condition that x and y are real numbers.
So, I will assume it is so.
If (3x-4y) + i(x+y) = 7 then
3x - 4y = 7, (1) (real part is 7)
x + y = 0. (2) (imaginary part is 0).
From (2), x = -y. Substitute it into (1). You will get
3*(-y) - 4y = 7, or
-7y = 7 ---> y = -1.
So, you just found y = -1.
Then x = -y = -(-1) = 1.
Answer. x = 1, y = -1.