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| Question 1044205:  Jess has a 4-digit code for her lock, but she has forgotten two of the digits.
 ?   8   5  ?
 Jess knows that her 4-digit code is:
 . less than 4000
 . odd
 . divisible by 3
 . made up of 4 different digits
 How many 4-digit codes are possible?
 (A)   3     (B)   5
 (C)   6     (D)   10
 Can someone show me the easy way for this number problem please.
 Thank you!
 
 Found 2 solutions by  ankor@dixie-net.com, kelvin nyawali:
 Answer by ankor@dixie-net.com(22740)
      (Show Source): 
You can put this solution on YOUR website! Jess has a 4-digit code for her lock, but she has forgotten two of the digits. ? 8 5 ?
 Jess knows that her 4-digit code is:
 . less than 4000
 . odd
 . divisible by 3
 . made up of 4 different digits
 How many 4-digit codes are possible?
 :
 Let's just start with what we do know. We can fine tune our method as we go along.
 :
 less then 4000, therefore the first 3 digit possibilities are:
 185 _
 285 _
 385 _
 :
 final number is odd and not a repeat
 :
 The final digit of 185_: 3,7,9. With a calc see which ones are divisible by 3
 1857 is so that's one possibility
 :
 The final digit of 285_: 1,3,7,9. With a calc see which ones are divisible by 3
 2853 is therefore 2859 also has to be, (a difference of 6) so that's three possibilities
 :
 The final digit of 385_: 1,7,9. With a calc see which ones are divisible by 3
 None are divisible
 :
 The answer is A. 3
Answer by kelvin nyawali(1)
      (Show Source): 
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