SOLUTION: Is there a faster method to factorise the equation x^3 - 2(1+i)x^2 + 3ix + (1-i) = 0, I used the factor theorem to find one factor then long division to find the others, however i

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: Is there a faster method to factorise the equation x^3 - 2(1+i)x^2 + 3ix + (1-i) = 0, I used the factor theorem to find one factor then long division to find the others, however i      Log On


   



Question 1027086: Is there a faster method to factorise the equation x^3 - 2(1+i)x^2 + 3ix + (1-i) = 0, I used the factor theorem to find one factor then long division to find the others, however it was a very long process so I was wondering if there is a quicker method? Thanks
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
A little guesswork gives x = 1 is a solution to the equation. Upon using synthetic division to find the quotient after dividing by x-1, you get x%5E2+-+%281%2B2i%29x+%2B+%28-1%2Bi%29+=+0.
Using the quadratic formula directly on the last quadratic equation gives the solutions i and 1+i.
==> x%5E3+-+2%281%2Bi%29x%5E2+%2B+3ix+%2B+%281-i%29++=+%28x-1%29%28x-i%29%28x-1-i%29