SOLUTION: what does |x-1/3| less than 16/3 equal?
i tried splitting the problem into two:
[(x-1/3) less than 16/3] and [(x-1/3) greater than -16/3]
this was not correct. what was wrong?
Algebra ->
Absolute-value
-> SOLUTION: what does |x-1/3| less than 16/3 equal?
i tried splitting the problem into two:
[(x-1/3) less than 16/3] and [(x-1/3) greater than -16/3]
this was not correct. what was wrong?
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Question 919603: what does |x-1/3| less than 16/3 equal?
i tried splitting the problem into two:
[(x-1/3) less than 16/3] and [(x-1/3) greater than -16/3]
this was not correct. what was wrong? Found 2 solutions by josgarithmetic, MathLover1:Answer by josgarithmetic(39623) (Show Source):
You can put this solution on YOUR website! What? That is an inequality. An inequality is an inequality. The left side unequal to the right side according to the ordering used.
You indicate . The inequality just is.
Your next statement could use some analysis and maybe solving of the inequality.
If the argument inside absolute value function is zero or positive, then:
If the argument is negative, then:
Multiply both sides by NEGATIVE 1, which reverses the order symbol,
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The solution is, EITHER OR ;
when you put both of these solution parts together, they share a set of values: .