SOLUTION: i am doing calculus but im stuck on the absolute value part of the equation y= abs value of x^2-8x+7 im cinfused as to what numbers stay positive or become negative

Algebra ->  Absolute-value -> SOLUTION: i am doing calculus but im stuck on the absolute value part of the equation y= abs value of x^2-8x+7 im cinfused as to what numbers stay positive or become negative      Log On


   



Question 736488: i am doing calculus but im stuck on the absolute value part of the equation
y= abs value of x^2-8x+7
im cinfused as to what numbers stay positive or become negative

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Any ( x,y) points that have a negative y will get
" flipped " about the x-axis, so that those y's
are now positive, and x remains the same
------------
Here's the plot:
+y+=+x%5E2+-+8x+%2B+7+
+graph%28+400%2C+400%2C+-10%2C+10%2C+-10%2C+10%2C+abs%28+x%5E2+-+8x+%2B+7+%29+%29+