SOLUTION: Suppose you buy flour and cornmeal in bulk to make flour tortillas and corn tortillas. Flour cost $1.50/lb. Cornmeal cost $2.50/lb. You want to spend less than $9.50 on flour and c

Algebra ->  Absolute-value -> SOLUTION: Suppose you buy flour and cornmeal in bulk to make flour tortillas and corn tortillas. Flour cost $1.50/lb. Cornmeal cost $2.50/lb. You want to spend less than $9.50 on flour and c      Log On


   



Question 733744: Suppose you buy flour and cornmeal in bulk to make flour tortillas and corn tortillas. Flour cost $1.50/lb. Cornmeal cost $2.50/lb. You want to spend less than $9.50 on flour and cornmeal, and you need at least 4 lb altogether.
a. Write a system of inequalities that describes this situation.
b. What are 2 possible solutions to this situation?

Found 2 solutions by josmiceli, fcabanski:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = pounds of flour needed
Let +b+ = pounds of cornmeal needed
Let +C+ = cost
+C+=+1.5a+%2B+2.5b+
+C+%3C+9.5+
+a+%2B+b+%3E=+4+
+1.5a+%2B+2.5b+%3C+9.5+
--------------------
(1) +3a+%2B+5b+%3C+19+
(2) +a+%2B+b+%3E=+4+
-----------------
I can see that +a+%3C+19%2F3+, so
+a+%3C+6.33+
and +a+%3E=+4+
+4+%3C=+a+%3C+6.33+
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and +b+%3C+19%2F5+
+b+%3C+3.8+
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Solutions:
So, I can say +a+=+5+ and +b+=+3%2F5+
and, also +a+=+4+ and +b+=+6%2F5+
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check:
+a+=+5+ and +b+=+3%2F5+
(1) +3a+%2B+5b+%3C+19+
(1) +3%2A5+%2B+5%2A%283%2F5%29+%3C+19+
(1) +15+%2B+3+%3C+19+
and
(2) +a+%2B+b+%3E=+4+
(2) +5+%2B+3%2F5+%3E=+4+
---------------------
+a+=+4+ and +b+=+6%2F5+
(1) +3a+%2B+5b+%3C+19+
(1) +3%2A4+%2B+5%2A%286%2F5%29+%3C+19+
(1) +12+%2B+6+%3C+19+
and
(2) +a+%2B+b+%3E=+4+
(2) +4+%2B+6%2F5+%3E=+4+
OK


Answer by fcabanski(1391) About Me  (Show Source):
You can put this solution on YOUR website!
Problems like this require two equations. The first equation describes the amount. The second equation describes cost.


Call flour f and cornmeal c.


f + c >= 4 - the total amount is greater or equal to 4 lbs. You need at least 4 lbs - 4 lbs or more.


1.5f + 2.5c < 9.50 - the cost of each is # of lbs times the cost per pound. And their sum must be less than $9.50.


Solve the first equation for f in terms of c, then replace f in the second equation with that value.


f >= 4 - c.


Since it's greater than or equal to 4-c, one valid solution results from it being equal. So just use equal.


1.5(4-c) + 2.5c < 9.50


6 - 1.5c +2.5c < 9.50


c < 3.5


Replace a valid value into the f = 4-c equation. 3 is less than 3.5.


f = 4-3 = 1.


Another solution is c = 2 lbs (that's less than 3.5)


f = 4-2 = 2.