SOLUTION: The length of a rectangle is 20 meters longer than the width. The perimeter must be between 80 and 100 meters. What are the possible values for the width of the rectangle?

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Question 691345: The length of a rectangle is 20 meters longer than the width. The perimeter must be between 80 and 100 meters. What are the possible values for the width of the rectangle?
Answer by mouk(232) About Me  (Show Source):
You can put this solution on YOUR website!
let +x+ = width of rectangle, then length = +x+%2B+20+
so, perimeter = +x+%2B+x+%2B+%28x%2B20%29+%2B+%28x%2B20%29+ = +4x+%2B+40+
but, The perimeter must be between 80 and 100 meters
so +80+%3C=+4x+%2B+40+%3C=+100+
consider, +80+%3C=+4x+%2B+40+ then +4x+%2B+40+%3E=+80
so +4x+%3E=+40
so +x+%3E=+10
Now consider +4x+%2B+40+%3C=+100+
so +4x+%3C=+60+
so +x+%3C=+15+
Hence solution is +10+%3C=+x+%3C=+15+