SOLUTION: 3-*absolutevaluesign* 2(x-5)+12 *absolutevaluesign* < 4

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Question 671476: 3-*absolutevaluesign* 2(x-5)+12 *absolutevaluesign* < 4
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
3-*absolutevaluesign* 2(x-5)+12 *absolutevaluesign* < 4
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3 - |2(x-5)+12| < 4
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|2(x-5)+12| > -1
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Since an "absolute value" is never negative,
the inequality is true for all values of "x".
Ans: All Real Numbers.
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Cheers,
Stan H.