You can put this solution on YOUR website! What steps do I take to solve -2|x+4|+10(less than or equal to) 16?
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-2|x+4|+10≤ 16
solve for 2 conditions: (x+4)>0 and (x+4)<0
-2(x+4)+10≤ 16
-2x-8+10≤ 16
-2x≤14
divide by -2 and reverse inequality sign
x≥-7 (reject, does not check)
..
2(x+4)+10≤ 16
2x+8+10≤ 16
2x≤-2
x≤-1
number line
<==-1].......>
solution: (-∞,-1]
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