SOLUTION: Solve the following inequality. Write the answer in interval notation. If the answer includes more than one interval write the intervals separated by the "union" symbol, U. If need

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Question 644555: Solve the following inequality. Write the answer in interval notation. If the answer includes more than one interval write the intervals separated by the "union" symbol, U. If needed enter as "infinity".
1[3x+5]+5<=30
[ and ] are verical bars :)
Please help me!
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website!
1|3x+5|+5 <= 30

1|3x+5| <= 30-5

1|3x+5| <= 25

|3x+5| <= 25/1

|3x+5| <= 25

3x+5 <= 25 and 3x+5 >= -25

-25 <= 3x+5 <= 25

-25-5 <= 3x <= 25-5

-30 <= 3x <= 20

-30/3 <= x <= 20/3

-10 <= x <= 20/3

So the answer in interval notation is $\left[-10,\frac{20}{3}\right]$

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