Someone Help Please
solve |3x+5| - 7 > -5 answer in interval notation
First isolate the absolute value on the left by ading
7 to both sides
|3x+5| - 7 > -5
+7 +7
-----------------
|3x+5| > 2
There are two rules for removing absolute value bars
1. To remove the absolute value bars of
|expression| < A , where A is a positive number,
replace it by this:
-A < expression < +A
2. To remove the absolute value bars of
|expression| > A , where A is a positive number,
replace it by this:
expression < -A OR expression > A
Since |3x+5| > 2 involves >, we replace it by:
3x + 5 < -2 OR 3x + 5 > 2
-5 -5 -5 -5
------------ -------------
3x < -7 OR 3x > -3
x < -7/3 OR x > -1
<=========o-----------o==========>
-7/3 -1
(-¥, -7/3) È (-1, ¥)
Edwin
