SOLUTION: |x^2+8x|=16 i tried multiple times please help.I can not solvw it

Algebra ->  Absolute-value -> SOLUTION: |x^2+8x|=16 i tried multiple times please help.I can not solvw it      Log On


   

Question 496409: |x^2+8x|=16 i tried multiple times please help.I can not solvw it
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
There are 2 possible values for +x%5E2+%2B+8x+,
either 16 or -16
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If +x%5E2+%2B+8x+=+16+
+x%5E2+%2B+8x+%2B+%288%2F2%29%5E2+=+16+%2B+%288%2F2%29%5E2+
+x%5E2+%2B+8x+%2B+16+=+32+
+%28x+%2B+4%29%5E2+=+32+
Take the square root of both sides
+x+%2B+4+=+4%2Asqrt%282%29+
+x+=+4%2A%28sqrt%282%29+-+1%29+ solution #1
also
+x+%2B+4+=+-4%2Asqrt%282%29+
+x+=+-4%2A%28sqrt%282%29+%2B+1%29+ solution #2
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If +x%5E2+%2B+8x++=+-16+
+x%5E2+%2B+8x+%2B+16+=+0+
+%28+x+%2B+4+%29%5E2+=+0+
Take the square root of both sides
+x+%2B+4+=+0+
+x+=+-4+ solution #3
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You can check solutions by plugging them back into
+x%5E2+%2B+8x+