Question 474142: Hi. I need help figuring out the absolute value of 3-2x=the absoulute value of 2x+3. Thank you so much. Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! |3-2x|=|2x+3|
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3-2x=0
-2x=-3
x=3/2 inflection point after which 3-2x is less than 0 because it has a negative slope.
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2x+3=0
2x=-3
x=-3/2 infection point after which 2x+3 increases in value because the slope is positive.
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X(-infinity, -3/2)
-(2x+3)=(3-2x) [2x+3 is negative below x=-3/2]
-2x-3=3-2x
0=6 No answer
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X(-3/2, 3/2)
3-2x=2x+3 [both statements are positive between x=-3/2 and 3/2]
-4x=0
x=0
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X(3/2, infinity)
-(3-2x)=2x+3 [3-2x is negative above x=3/2]
2x-3=2x+3
0=6 no answer
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x=0 the only answer
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Ed
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