SOLUTION: the length of a wire is 6.26m,a student measured it as 6.17. what is the percentage error?

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Question 1178051: the length of a wire is 6.26m,a student measured it as 6.17. what is the percentage error?
Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

the length of a wire is 6.26m,a student measured it as 6.17.
what is the percentage error?
6.26m=++6.17m%2B%28x%2F100%296.26m
6.26m-++6.17m=x%2A0.0626m
x%2A0.0626m=0.09m
x=0.09%2F0.0626
x=0.09%2F0.0626
x1.4377%->the percentage error

Answer by ikleyn(52847) About Me  (Show Source):
You can put this solution on YOUR website!
.
the length of a wire is 6.26 m,a student measured it as 6.17 highlight%28m%29. What is the percentage error?
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To find the percentage error,


    - first find the difference,

    - then relate it to the base value, which is 6.26 meters in this case,

    - and then multiply this ratio by 100 to get the percentage.



By knowing the rule, make all these calcs in one line


    the percentage error =  %28%286.26-6.17%29%2F6.26%29%2A100 = 1.44%  (rounded).      ANSWER

Solved.


  *  *  *  M E M O R I Z E     this mantra and use / repeat it every time when you need solve such problems.  *  *  *


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