SOLUTION: A t-shirt design company is dying purple shirts for a school club. The shirts came out too light so the company needs to add more pure blue dye to the mixture to get a darker purp

Algebra ->  Absolute-value -> SOLUTION: A t-shirt design company is dying purple shirts for a school club. The shirts came out too light so the company needs to add more pure blue dye to the mixture to get a darker purp      Log On


   



Question 1168985: A t-shirt design company is dying purple shirts for a school club. The shirts came out too light so the company needs to add more pure blue dye to the mixture to get a darker purple color for the shirts. The full vat of color holds 54 gallons of the original dye that is 27% blue. How many gallons should be drained and replaced with pure blue dye so that the mixture will be 40% blue?
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
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A t-shirt design company is dying purple shirts for a school club. The shirts came out too light so the company needs to add
more pure blue dye to the mixture to get a darker purple color for the shirts. The full vat of color holds 54 gallons
of the original dye that is 27% blue. How many gallons should be drained and replaced with pure blue dye so that the mixture will be 40% blue?
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Let V be the volume to drain off from 54 gallons of the 27% solution.


Step 1:  Draining.  After draining,  you have (54-V) gallons of the 27% acid solution.



Step 2:  Replacing.  Then you add V gallons of the pure blue dye (the replacing step).

                     After the replacing,  you have the same total liquid volume of 54 gallons.


It contains  0.27*(54-V) + V   of pure blue dye.



So, your "concentration equation" is


    %280.27%2A%2854-V%29+%2B+V%29%2F54 = 0.4.    (1)



At this point, the setup is done and completed.



Now you need to solve your basic equation  (1).

As the first step, multiply both sides by 80, and then simplify


    0.27*(54-V) + V = 0.4*54

    14.58 - 0.27V + V = 21.6

    0.73V = 21.6 - 14.58 = 7.02

    V = 7.02%2F0.73 = 9.616.


ANSWER.  9.616 gallons of the 27% solution should be drained and replaced by the pure blue duy.


CHECK.   %280.27%2A%2854-9.616%29+%2B+9.616%29%2F54 = 0.4.    ! Precisely correct !

Solved.

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There is entire bunch of lessons covering various types of mixture problems
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions (*)
    - Word problems on mixtures for dry substances like coffee beans, nuts, cashew and peanuts
    - Word problems on mixtures for dry substances like candies, dried fruits
    - Word problems on mixtures for dry substances like soil and sand
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
    - Advanced mixture problems
    - Advanced mixture problem for three alloys
    - OVERVIEW of lessons on word problems for mixtures
in this site.

A convenient place to quickly observe these lessons from a  "bird flight height"  (a top view)  is the last lesson in the list.

Read them and become an expert in solution the mixture word problems.

Specially for "draining - replacing" mixture problems see the lesson marked (*) in the list.


Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Mixture problems".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.