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Let
Use quadratic formula
and
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Get a 2nd opinion if needed
Tutor Josmiceli gave these four answers:
His work was correct up to that point. But he didn't finish.
1. He didn't rule out the two extraneous answers.
2. He didn't simplify the two answers which are solutions.
His second and fourth answers are negative which are not in
the domain of the log function. So the only solutions are
or
However they are not in simplest radical form, as they
contain a square root inside a square root.
We set
where u and v are rational.
Square both sides:
We equate the terms without square roots and
equate terms with square roots, and we have this
system:
Divide the second equation through by
Squaring both sides:
Substituting in
Multiply through by u2; ; ;
Since we assumed u and v are rational, we discard
the second answers for u.
Therefore:
However we must discard the negative values and
as extraneous.
So the only two solutions in simplified form are
Edwin