SOLUTION: for how many positive integers x is 130/x an integer? a.8 b.7 c.6 d.d

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Question 1095883: for how many positive integers x is 130/x an integer?
a.8 b.7 c.6 d.d

Answer by ikleyn(52793) About Me  (Show Source):
You can put this solution on YOUR website!
.
The integer number 130 has this decomposition into the product of these prime numbers:

130 = 2.5.13 = 2%5E1.5%5E1.13%5E1.


Note that the indexes are 1 for 2, 1 for 5 and 1 for 13.


Now add 1 to each of the three indexes:

1 + 1 = 2  (for 2);

1 + 1 = 2  (for 5);

1 + 1 = 2  (for 13).


Now the number of all divisors for 130 (including 1 and including 130 itself) is the product 2*2*2 = 8.


They are

1   = 2%5E0%2A5%5E0%2A13%5E0,

2   = 2%5E1%2A5%5E0%2A13%5E0,

5   = 2%5E0%2A5%5E1%2A13%5E0,

10  = 2%5E1%2A5%5E1%2A13%5E0,

13  = 2%5E0%2A5%5E0%2A13%5E1,

26  = 2%5E1%2A5%5E0%2A13%5E1,

65  = 2%5E0%2A5%5E1%2A13%5E1,

130 = 2%5E1%2A5%5E1%2A13%5E1.

The answer to your problem is the option a): there are 8 divisors.