SOLUTION: O.k. tell my where I'm going wrong here: |2x-3|+4=2-----> 2x-3+4=2-4----->2x-3=-2---->2x-3+3=-2+3---->2x=1---->2x/2=1/2----->x=.50
and if you ad a negative to =2--->=-2---->answ
Algebra ->
Absolute-value
-> SOLUTION: O.k. tell my where I'm going wrong here: |2x-3|+4=2-----> 2x-3+4=2-4----->2x-3=-2---->2x-3+3=-2+3---->2x=1---->2x/2=1/2----->x=.50
and if you ad a negative to =2--->=-2---->answ
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Question 1044834: O.k. tell my where I'm going wrong here: |2x-3|+4=2-----> 2x-3+4=2-4----->2x-3=-2---->2x-3+3=-2+3---->2x=1---->2x/2=1/2----->x=.50
and if you ad a negative to =2--->=-2---->answer is x=-1.50
but both these answers are with in the hash marks, with another number and
which you just ignore the polarity and consider it positive?
as you can see I'm in a world of confusion here! ha
how do I make sense of all this
thanks Answer by josgarithmetic(39623) (Show Source):
Solve first just for the absolute value, if it can be isolated.
THIS is impossible.
NO SOLUTION.
An absolute value is not a signed number, and can never be considered negative. An absolute value itself is never less than zero.
The expression inside the absolute value machine may be positive, or zero, or negative. The absolute value machine, once it contains a number, will only produce either a non-signed, ASSUMED POSITIVE value, OR zero.