SOLUTION: If the volume of a box is 60ft^3, the width is 3ft, the height is 6 more than the length, what is the length? I have been trying this for HOURS.
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Question 944408: If the volume of a box is 60ft^3, the width is 3ft, the height is 6 more than the length, what is the length? I have been trying this for HOURS. Found 2 solutions by Alan3354, macston:Answer by Alan3354(69443) (Show Source):
Quadratic equation (in our case ) has the following solutons:
For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=116 is greater than zero. That means that there are two solutions: .
Quadratic expression can be factored:
Again, the answer is: 2.3851648071345, -8.3851648071345.
Here's your graph:
Answers 2.385, -8.385 ANSWER L=2.385 (the other answer reverses L and H)
60 cu ft = (2.385 ft)(3 ft)H
60 cu ft=7.155H sq ft divide each side by 7.155 sq ft
8.386 ft=H
CHECK
60 cu ft=L*W*H
60 cu ft=(2.385 ft)(3 ft)(8.386 ft)
60 cu ft=60 cu ft