SOLUTION: Hello Tutors of Algebra.com,
I don't if is the right section but here goes
A lab technician has a 40% alcohol solution and a 60% alcohol solution. He needs to make 100 mL of
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-> SOLUTION: Hello Tutors of Algebra.com,
I don't if is the right section but here goes
A lab technician has a 40% alcohol solution and a 60% alcohol solution. He needs to make 100 mL of
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Question 483296: Hello Tutors of Algebra.com,
I don't if is the right section but here goes
A lab technician has a 40% alcohol solution and a 60% alcohol solution. He needs to make 100 mL of solution that is 48% alcohol . How much of each available solution should he use ?
thanks in advance :D Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A lab technician has a 40% alcohol solution and a 60% alcohol solution. He needs to make 100 mL of solution that is 48% alcohol . How much of each available solution should he use ?
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Equation:
alcohol + alcohol = alcohol
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0.40x + 0.60(100-x) = 0.48*100
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Multiply thru by 100 to get:
40x + 60*100 - 60x = 48*100
-20x = -12*100
x = 60 mL (amt. of 40% solution needed)
100-x = 40mL (amt. of 60% solution needed)
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Cheers,
Stan H.
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