SOLUTION: If the volume of an orange is 523.3 cubic cm, what would be the edible volume of the orange if the peel is 0.5 cm thick? What would be the percent of edible orange?

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Question 333296: If the volume of an orange is 523.3 cubic cm, what would be the edible volume of the orange if the peel is 0.5 cm thick? What would be the percent of edible orange?
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
volume with peel = 523.3 cu.cm
volume of sphere = %284%2F3%29%2Api%2Ar%5E3
+523.3+=+%284%2F3%29%2Api%2Ar%5E3
r%5E3=%283%2A523.3%2F%284%2Api%29%29
r%5E3=124.93+
r= 5 cm
...
The peel is 0.5 cm thick
the diameter of of edible orange will be 5-1 cm = 4cm
..
Volume edible part = +%284%2F3%29%2Api%2A4%5E3%29
= 268 cu. cm
...
percent of edible volume = (268/523.3)*100
= 51.21 %