Solver Surface area and Volume of a pyramid.

Source code of 'Surface area and Volume of a pyramid.'

This Solver (Surface area and Volume of a pyramid.) was created by by hummingbird(0)

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==section input

Input the following parameters of the pyramid:
L is the length of the square base
H is the perpendicular height of the vertex from the base
H = *[input h=1] and L = *[input l=1]

==section solution
perl
if($r<=0 || $l<=0){
print" Please enter the positive values ( >0 ) of parameter!!!";
}
else{
my $s = sqrt((1/4)*$l*$l+$h*$h);
my $p = 4*$l;
my $a = $l*$l;
my $sa = (1/2)*$p*$s;
my $sa2 = $sa+ $a;
my $v = (1/3)*$a*$h;

print "
This formula is for the square base pyramid whose side length is 'L' and Height 
of the pyramid is 'H'

The surface area (SA) of a pyramid is given by{{{SA = A + ((P*S)/2)}}} 
where: 
A is the area of the base
P is the perimeter of the base
S is the slant height along the bisector of a face (i.e. the length from the midpoint 
of any edge of the base to the top)
{{{S= sqrt((L/2)^2+H^2)}}} 
L is the length of the square base
H is the perpendicular height of the vertex from the base

The volume of the cone can be found by the formula {{{V=(1/3)*A*H}}}

In our case the desired values are thus:

S = {{{sqrt((1/4)*$l*$l+$h*$h) = $s}}}

SA = {{{$a+ (1/2)*$p*$s= $sa2}}}
SA = {{{$l*$l+ (1/2)*4*$l*$s= $sa2}}}
V = {{{(1/3)*$a*$h = $v}}}

For more on this topic, refer to <A HREF=Pyramid_%28geometry%29.wikipedia>Pyramid</A> 
";
}
==section output
s, sa, v,

==section check
  h=3 L=1 s=4.03112887 sa=8.0622577 v=1