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Tutors Answer Your Questions about Vectors (FREE)
Question 89040: Can someone tell me if this is correct, and also I need to round it to the nearest tenth but I don't know how.......A plane with an airspeed of 450 mph if flying in the direction N35degrees West....im supposed to express the vector in terms of i&j......
my answer is -450sin35i + 450cos35j
Click here to see answer by stanbon(75887) |
Question 91857: a mine shaft goes straight down for 110m. from its lower end a horizontal tunnel goes 35m east and then 70m south to its end.what is the displacement from the top of the shaft to the end of the tunnel?what angle does this displacement make with respect to the vertical line?
Click here to see answer by ankor@dixie-net.com(22740)  |
Question 98494: The question is
Show that there are no vectors u and v such that the magnitude of u=1, the magbnitude of v=2, and the (dot product) u*v=3.
Hope this makes sense. It is easier to understand with the symbols that they use.
I wasn't even sure how to start this problem. All I could get was 1*2 which doesn't =3 but that seems too easy.
Click here to see answer by jim_thompson5910(35256) |
Question 106431: Hey again! :D Im stuck on this question about vectors including acceleration and relative positioning.
The question is..
A particle has position 2i + j initially and is moving with speed 10ms-1 in the direction 3i - 4j. Find it's position vector when t = 3 and the distance it has travelled in those 3 seconds.
I know the distance travelled is Speed * time, so 10 * 3 = 30metres. But when i worked out the relative position i got it totally wrong, does anyone know how to do this? Thanks alot in advance! :D
Click here to see answer by Fombitz(32388)  |
Question 106431: Hey again! :D Im stuck on this question about vectors including acceleration and relative positioning.
The question is..
A particle has position 2i + j initially and is moving with speed 10ms-1 in the direction 3i - 4j. Find it's position vector when t = 3 and the distance it has travelled in those 3 seconds.
I know the distance travelled is Speed * time, so 10 * 3 = 30metres. But when i worked out the relative position i got it totally wrong, does anyone know how to do this? Thanks alot in advance! :D
Click here to see answer by stanbon(75887) |
Question 106431: Hey again! :D Im stuck on this question about vectors including acceleration and relative positioning.
The question is..
A particle has position 2i + j initially and is moving with speed 10ms-1 in the direction 3i - 4j. Find it's position vector when t = 3 and the distance it has travelled in those 3 seconds.
I know the distance travelled is Speed * time, so 10 * 3 = 30metres. But when i worked out the relative position i got it totally wrong, does anyone know how to do this? Thanks alot in advance! :D
Click here to see answer by MathLover1(20849)  |
Question 106434: Hey again! :D
A particle has position 2i + j initially and is moving with speed 10ms-1 in the direction 3i - 4j. Find it's position vector when t = 3 and the distance it has travelled in those 3 seconds.
I know the distance travelled is Speed * time, so 10 * 3 = 30metres.
I have already posted this topic, because the people gave the correct answers, ( thanks alot to you all for helping! :P )
but i still dont understand how you got them, i thought, if in 1 second, you do 3i - 4j
then in 3 seconds you do, 9i - 12j, add on the original, so 11i - 11j,
i have no idea how you got to 20i and 23j, i can see with 3i-4j, if you multiply everythign by 6, you get a figure that once added to the original 2i + j, gives the answer, but again why 6? :( Thanks again in advanced
Click here to see answer by Fombitz(32388)  |
Question 106434: Hey again! :D
A particle has position 2i + j initially and is moving with speed 10ms-1 in the direction 3i - 4j. Find it's position vector when t = 3 and the distance it has travelled in those 3 seconds.
I know the distance travelled is Speed * time, so 10 * 3 = 30metres.
I have already posted this topic, because the people gave the correct answers, ( thanks alot to you all for helping! :P )
but i still dont understand how you got them, i thought, if in 1 second, you do 3i - 4j
then in 3 seconds you do, 9i - 12j, add on the original, so 11i - 11j,
i have no idea how you got to 20i and 23j, i can see with 3i-4j, if you multiply everythign by 6, you get a figure that once added to the original 2i + j, gives the answer, but again why 6? :( Thanks again in advanced
Click here to see answer by scott8148(6628)  |
Question 107895: Its the kinematic section in the mechanics book. I dont understand how to do question 1a, i can do 1b :D
It is.
A ball is thrown vertically upwards with a speed of 10ms-1 from a point 2m above the ground. (a) Calculate the length of time for which the ball is 3m or more above the ground.
I have no idea how to deal with this type of question where it starts above the ground, and we have to find how long it is above a certain point, if some one could help it would be greatly appreicated! Thanks! :D
Click here to see answer by scott8148(6628)  |
Question 107896: Hey again! This is also impossible, i can do question 3 but not 2! :D
A racing car is moving with constant acceleration along a straight stretch of road. The car passes point A at 0s, travelling at 18ms - 1, point B at 3s and point C at 7s, travelling at 53ms - 1. Calculate:
A - acceleration of the car
B - Speed of the car at B
C - the distance from B to C.
I've tried all three parts and failed miserably as i have the answers in the back of the book, i have no clue! :( Thanks alot in advance! :D
Click here to see answer by scott8148(6628)  |
Question 107897: I could do 4a. But not 4b, its hard! :o
Question 4.
A girl throws a ball vertically upwards with speed 8ms-1 from a window which is 6m above horizontal ground.
(a) find the greatest height above the ground reached by the ball. - completed, i got 9.3 metres which was correct.
1.5 seconds later she drops a second ball from rest out of the same window.
(b) Find the distance below the window of the point where the balls meet.
I cant do (b) can any one help? Thanks alot in advance! :D
Click here to see answer by scott8148(6628)  |
Question 107432: I tried to solve this and I have had problems.
I have got 3 equations so far. There is one more needed.
f >=0
r >=0
f>2r
A toy manufacturer is introducing two new dolls, My First Baby and My Real Baby. In one hour, the company produces at least twice as many First Babies as Real Babies. The company spends no more than 48 hours a week making these dolls. The profit on each First Baby is $3.00 and the profit on each Real Baby is $7.50. Find the number an type of dolls that should be produced to maximize profit.
I can do the last part of finding the maximum profit but I need a 4th equation which I have problems translating from text. If you could help my thanks go to you. I appreciate your effort even if you do not answer this question.
Click here to see answer by stanbon(75887) |
Question 123129: If Earthquake 1 measures 6.2 on the Richter scale, and Earthquake 2 measures 8.2 on the Richter scale, how many times bigger was Earthquake 2 than Earthquake 1? (Rephrased: By what factor was Earthquake 2 bigger than Earthquake 1?)
Click here to see answer by Fombitz(32388)  |
Question 145667: I own a very beautiful, and somewhat massive, boat. Each year, in the fall, I drag it totally out of the water with my tractor--the tension in the drag line is 5000 lbs. This year, my tractor died, and I must get the boat out by myself. All I have is lots of high tension cable (that doesn't stretch at all!!). Can I do it by myself? There are lots of massive trees all over the place. I'm fairly strong for an old guy--can manage a tension of about 300 lbs.
Click here to see answer by Fombitz(32388)  |
Question 149681: 1. Find the magnitude of the following vector: v = -2i - 4j.
2. Find the unit vector that has the same direction as the vector below: v = 4j
3. In what quadrant is the terminal point of the vector below located?
v = 5i - 3j
4.The vector, v, is multiplied by a scalar as shown below. v = -i + j -3(v)
Click here to see answer by Fombitz(32388)  |
Question 155178: Greetings, I am currently in Physical Science and right off the bat we started on vectors, motion, and Newtons Law. Anyway, I haven't been in a College atmosphere in quite a while. So I need some serious help!!! This will sound silly yet I for some reason can not get it. Here it is: Two cars leave a cross roads at the same time. One heads north at 50Km/h and the other heads east at 70Km/h. How far apart are the cars after 2 hours?
Click here to see answer by Earlsdon(6294) |
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