SOLUTION: Find the angle between the vector a=< sqrt(3),-1> and b=<0,11>. Answer in radians.

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Question 967880: Find the angle between the vector a=< sqrt(3),-1> and b=<0,11>. Answer in radians.
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
Find the angle between the vector a=< sqrt(3),-1> and b=<0,11>. Answer in radians.
a=< sqrt(3),-1> and b=<0,11>


          a∙b
cos(q) = ——————  
         ∥a∥∥b∥

cos%28theta%29%22%22=%22%22%22%22=%22%22%280-11%29%2F%28sqrt%283%2B1%29sqrt%280%2B121%29%29%22%22=%22%22%28-11%29%2F%28sqrt%284%29sqrt%28121%29%29%22%22=%22%22%28-11%29%2F%282%2A11%29%22%22=%22%22-1%2F2 

theta%22%22=%22%222pi%2F3

Edwin