SOLUTION: A certain escalator travels at a rate of 10.6 m/min, and its angle of inclination is 32.5 degrees. What is the vertical component of the velocity? How long will it take a passeng
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Question 524889: A certain escalator travels at a rate of 10.6 m/min, and its angle of inclination is 32.5 degrees. What is the vertical component of the velocity? How long will it take a passenger to travel 10.0 m vertically? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A certain escalator travels at a rate of 10.6 m/min, and its angle of inclination is 32.5 degrees. What is the vertical component of the velocity? How long will it take a passenger to travel 10.0 m vertically?
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vertical component = 10.6*sin(32.5) = 5.64 m/min
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time to travel 10m = 10/5.64 = 1.7725 minutes = 1min 46.35 seconds
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Cheers,
Stan H.
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