SOLUTION: Determine the equation of the tangent to the curve y=((x^2)-1)/(3x) at x=2.

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Question 183432: Determine the equation of the tangent to the curve y=((x^2)-1)/(3x) at x=2.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Determine the equation of the tangent to the curve y=(x^2-1)/3x at x=2.
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y=(x^2-1)*x^-1/3 at x=2.
dy/dx = (1/3)*(2x*x^-1 + (x^2-1)*(-1)*(x^-2))
= %281%2F3%29%2A%282+-+%28x%5E2-1%29%2Fx%5E2%29
@ x = 2:
= (1/3)*(2 - 3/4)
= (1/3)*(5/4)
= 5/12