SOLUTION: A hockey puck of mass 0.245 kg leaves a hockey stick at a speed of 29 m/s. The coefficient of kinetic friction between the ice and puck is 0.080. What is the acceleration of the

Algebra ->  Vectors -> SOLUTION: A hockey puck of mass 0.245 kg leaves a hockey stick at a speed of 29 m/s. The coefficient of kinetic friction between the ice and puck is 0.080. What is the acceleration of the       Log On


   

Question 1185368: A hockey puck of mass 0.245 kg leaves a hockey stick at a speed of 29 m/s. The coefficient of kinetic friction between the ice and puck is 0.080.
What is the acceleration of the puck once it leaves the stick?
How long will it take for the puck to stop?
Repeat part (a) for a puck of twice the mass.
Answer by ikleyn(53956) About Me  (Show Source):
You can put this solution on YOUR website!
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A hockey puck of mass 0.245 kg leaves a hockey stick at a speed of 29 m/s.
The coefficient of kinetic friction between the ice and puck is 0.080.
What is the acceleration of the puck once it leaves the stick?
How long will it take for the puck to stop?
Repeat part (a) for a puck of twice the mass.
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The weight of the hockey puck is m*g , where g = 9.81 m/s^2 is the gravity acceleration
at the Earth surface.


The friction force is  F = k*m*g,  where  k = 0.08 is the friction coefficient.


The acceleration of the pack (which is the deceleration, in this case) is

    a = F%2Fm = %28k%2Am%2Ag%29%2Fm = k*g = 0.08*9.81 = 0.7848 m/s^2.


The puck will stop in

    t = v%2Fa = 29%2F0.7848 = 36.95 seconds  (rounded).

Solved.

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Having my solution as a TEMPLATE in front of you eyes, you may repeat these
calculations on your own as many times as you want (60 times, for example).