SOLUTION: Find the angle α between the vectors in radians a = (-2, 3), b = (6, 2)

Cosine of the angle between the vectors "a" and "b" is equal to the scalar product of the vectors "a" and "b", 
divided by the product of their lengths


     = .


So, you have:  the scalar product is (-2)*6 + 3*2 = -12 + 6 = -6;

               |a| =  = ;

               |b| =  = .


Therefore,   =  =  = -0.26312.


So,   = arccos(-0.26312) = 1.837 radians.     ANSWER